Bài giảng Strength of materials - Chương 5: Failure theories - Nguyễn Sỹ Lâm

CHAPTER 5: FAILURE THEORIES  
Failure – A part is permanently distorted (bị bóp méo) and will not function  
properly.  
A part has been separated into two or more pieces.  
Material Strength  
Sy = Yield strength in tension, Syt = Syc  
Sys = Yield strength in shear  
Su = Ultimate strength in tension, Sut  
Suc = Ultimate strength in compression  
Sus = Ultimate strength in shear = 0.67 Su  
CHAPTER 5: FAILURE THEORIES  
A ductile material deforms significantly before fracturing. Ductility is measured by %  
elongation at the fracture point. Materials with 5% or more elongation are considered  
ductile.  
Brittle material yields very little before fracturing, the  
yield strength is approximately the same as the ultimate  
strength in tension. The ultimate strength in compression  
is much larger than the ultimate strength in tension.  
FAILURE THEORIES – DUCTILE MATERIALS  
Yield strength of a material is used to design components made of  
ductile material  
• Maximum shear stress theory (Tresca 1886)  
(Thuyết bền: ứng suất tiếp lớn nhất – TB3)  
(max )component > ()obtained from a tension test at the yield point  
Failure  
Sy  
= Sy  
=
2
To avoid failure  
Sy  
2
(max )component  
<
= Sy  
n = Safety factor  
Design equation  
=Sy  
FAILURE THEORIES – DUCTILE MATERIALS  
SPECIAL CASES  
A special planar state of stress  
τxy= τ  
Sy  
   
TB3 2 42   
σx= σ  
2 2n  
Purely shear state of stress  
τxy= τ  
Sy  
   
  
2 2n  
FAILURE THEORIES – DUCTILE MATERIALS  
• Distortion energy theory (von Mises-Hencky)  
(Thuyết bền: Thế năng biến đổi hình dáng lớn nhất – TB4)  
Simple tension test → (Sy)t  
Hydrostatic state of stress → (Sy)h  
t  
h  
(Sy)h  
(Sy)t  
>>  
Distortion contributes to  
failure much more than  
change in volume.  
h  
h  
t  
(total strain energy) – (strain energy due to hydrostatic stress) = strain energy  
due to angular distortion > strain energy obtained from a tension test at the  
yield point → failure  
FAILURE THEORIES – DUCTILE MATERIALS  
The area under the curve in the elastic region is called the Elastic Strain Energy.  
U = ½ ε  
3D case  
UT = ½ 1ε1 + ½ 2ε2 + ½ 3ε3  
Stress-strain relationship  
2  
E
1  
3  
E
3  
1  
E
2  
v
v
v
ε1  
ε2  
ε3  
v
v
v
=
=
=
E
1  
E
E
2  
E
E
3  
E
1
2E  
2
2
2
UT =  
(1 + 2 + 3 ) - 2v (12 + 13 + 23)  
FAILURE THEORIES – DUCTILE MATERIALS  
Distortion strain energy = total strain energy – hydrostatic strain energy  
Ud = UT – Uh  
1
2E  
2
2
2
UT =  
(1 + 2 + 3 ) - 2v (12 + 13 + 23)  
(1)  
Substitute 1 = 2 = 3 = h  
1
2E  
2
2
2
Uh =  
(h + h + h ) - 2v (hh + hh+ hh)  
Simplify and substitute 1 + 2 + 3 = 3h into the above equation  
(1 + 2 + 3)2  
2
3h  
(1 – 2v)  
Uh =  
(1 – 2v) =  
2E  
6E  
Subtract the hydrostatic strain energy from the total energy to  
obtain the distortion energy  
1 + v  
(2 – 3)2  
(1 – 2)2 + (1 – 3)2 +  
(2)  
Ud = UT – Uh =  
6E  
FAILURE THEORIES – DUCTILE MATERIALS  
Strain energy from a tension test at the yield point  
Substitute in equation (2)  
1= Sy and 2 = 3 = 0  
1 + v  
(2 – 3)2  
(1 – 2)2 + (1 – 3)2 +  
Ud = UT – Uh =  
6E  
1 + v  
(S )2  
Utest =  
y
3E  
To avoid failure, Ud < Utest  
(2 – 3)2  
(1 – 2)2 + (1 – 3)2 +  
½
< Sy  
2
FAILURE THEORIES – DUCTILE MATERIALS  
(2 – 3)2  
(1 – 2)2 + (1 – 3)2 +  
½
< Sy  
2
2D case, 3 = 0  
½
2
2
(1 – 12 + 2 ) < Sy =   
Where  is von Mises stress  
Design equation  
FAILURE THEORIES – DUCTILE MATERIALS  
τxy= τ  
Pure torsion, = 1 = – 2  
2
2
2
(1 – 2 1 + 2 ) = Sy  
32 = Sy2  
Sy  
   
Sys = Sy / √ 3 →
or  
   
3 3n  
Relationship between yield strength in  
tension and shear  
1, 2 = x/2 ± [(x)/2]2 + (xy)2  
If y = 0, then  
the design equation can be written in terms of the dominant component  
stresses (due to bending and torsion)  
τxy= τ  
Sy  
   
2
2
TB4 1 31    
σx= σ  
3 3n  
FAILURE THEORIES – DUCTILE MATERIALS  
Distortion energy theory  
Sy  
Maximum shear stress theory  
Sy  
max =  
2n  
′ =  
n
Sy , Su  
• Select material: consider environment, density, availability →  
• Choose a safety factor  
n
Size Weight Cost  
The selection of an appropriate safety factor should be based  
on the following:  
Degree of uncertainty about loading (type, magnitude and direction)  
Degree of uncertainty about material strength  
Uncertainties related to stress analysis  
Consequence of failure; human safety and economics  
Type of manufacturing process  
Codes and standards  
FAILURE THEORIES – DUCTILE MATERIALS  
Design Process  
Use n = 1.2 to 1.5 for reliable materials subjected to  
loads that can be determined with certainty.  
Use n = 1.5 to 2.5 for average materials subjected to  
loads that can be determined. Also, human safety and  
economics are not an issue.  
Use n = 3.0 to 4.0 for well known materials subjected to  
uncertain loads.  
FAILURE THEORIES – DUCTILE MATERIALS  
Design Process  
Sy , Su  
• Select material, consider environment, density, availability →  
• Choose a safety factor  
• Formulate the von Mises or maximum shear stress in terms of size.  
• Use appropriate failure theory to calculate the size.  
Sy  
Sy  
max =  
′ =  
2n  
n
• Optimize for weight, size, or cost.  
FAILURE THEORIES – BRITTLE MATERIALS  
One of the characteristics of a brittle material is that the ultimate strength  
in compression is much larger than ultimate strength in tension.  
Suc  
>> Sut  
Mohr’s circles for compression and tension tests.  
Suc  
3  
1  
Stress  
state  
Sut  
Tension test  
Compression test  
Failure envelope  
The component is safe if the state of stress falls inside the failure envelope.  
1 > 3 and 2 = 0  
FAILURE THEORIES – BRITTLE MATERIALS  
Modified Coulomb-Mohr theory  
(Thuyết Bền Morh – TB5)  
3 or 2  
3 or 2  
Sut  
Sut  
I
Safe  
Safe  
Safe  
Sut  
Sut  
1  
Suc  
II  
-Sut  
Safe  
III  
Suc  
Suc  
Cast iron data  
Three design zones  
FAILURE THEORIES – BRITTLE MATERIALS  
Modified Coulomb-Mohr theory  
2  
Sut  
Zone I  
2 > 0  
and 1 > 2  
1 > 0 ,  
I
Sut  
Design equation  
1  
II  
-Sut  
Zone II  
III  
2 < 0  
and 2 < Sut  
1 > 0 ,  
Suc  
Design equation  
Zone III  
2 < 0  
and 2 > Sut  
1 > 0 ,  
Design equation  
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